-5k^2-36k+32=0

Solution for -5k^2-36k+32=0 equation:

-5k^2-36k+32=0

a = -5; b = -36; c = +32;
Δ = b2-4ac
Δ = -362-4·(-5)·32
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-44}{2*-5}=\frac{-8}{-10}
=4/5
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+44}{2*-5}=\frac{80}{-10}
=-8
$